# Line slope calculator x-10y=-20

**Straight line given by points A[0; 2] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.1x+2

**Canonical form of the line equation:**x-10y+20 = 0

**Parametric form of the line equation:**

x = 10t

y = t+2 ; t ∈ R

**Slope:**m = 0.1

**Slope angle of line: φ =**5°42'38″ = 0.0997 rad

**X intercept:**x

_{0}= -20

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.9901

**The length of the segment AB: |AB| =**10.0499

**Vector: AB =**(10; 1)

**Normal vector: n =**(1; -10)

**Midpoint of the segment AB: M =**[5; 2.5]

**Perpendicular Bisector equation:**10x+y-52.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 73°18'3″ = 1.2793 rad**