#### Answer

(a) Roman is farsighted.
(b) His near point without the lenses is $~~0.50~m$

#### Work Step by Step

(a) The prescription has a positive value. This means that the lens is a converging lens. Therefore, Roman is farsighted.
(b) We can find the location of the image:
$P = \frac{1}{s}+\frac{1}{s'}$
$\frac{1}{s'} = P - \frac{1}{s}$
$\frac{1}{s'} = 2.0~m^{-1} - \frac{1}{0.25~m}$
$\frac{1}{s'} = -2.0~m^{-1}$
$s' = -0.50~m$
His near point without the lenses is $~~0.50~m$